b^2-27b=60

Solution for b^2-27b=60 equation:

b^2-27b=60

We move all terms to the left:

b^2-27b-(60)=0

a = 1; b = -27; c = -60;
Δ = b2-4ac
Δ = -272-4·1·(-60)
Δ = 969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{969}}{2*1}=\frac{27-\sqrt{969}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{969}}{2*1}=\frac{27+\sqrt{969}}{2}
$